◄QuickSCREEN► ◄Details► ◄Example► ◄Contents► ◄Index► ────────────────────────────────────────────────────────────────────────────── CDBL Programming Example The following example demonstrates how the precision of the numeric expression affects the result of using CDBL: X = 7/9 X# = 7/9 PRINT X 'Both X# and CDBL(X) will be accurate to only 7 decimal 'places, because 7/9 is evaluated in single precision. PRINT X# PRINT CDBL(X) 'Accurate to 15 decimal places. PRINT 7#/9# Sample Output .7777778 .7777777910232544 .7777777910232544 .7777777777777778